public class Solution extends Object
2234 - Maximum Total Beauty of the Gardens.
Hard
Alice is a caretaker of n
gardens and she wants to plant flowers to maximize the total beauty of all her gardens.
You are given a 0-indexed integer array flowers
of size n
, where flowers[i]
is the number of flowers already planted in the ith
garden. Flowers that are already planted cannot be removed. You are then given another integer newFlowers
, which is the maximum number of flowers that Alice can additionally plant. You are also given the integers target
, full
, and partial
.
A garden is considered complete if it has at least target
flowers. The total beauty of the gardens is then determined as the sum of the following:
full
.partial
. If there are no incomplete gardens, then this value will be 0
.Return the maximum total beauty that Alice can obtain after planting at most newFlowers
flowers.
Example 1:
Input: flowers = [1,3,1,1], newFlowers = 7, target = 6, full = 12, partial = 1
Output: 14
Explanation: Alice can plant
2 flowers in the 0th garden
3 flowers in the 1st garden
1 flower in the 2nd garden
1 flower in the 3rd garden
The gardens will then be [3,6,2,2]. She planted a total of 2 + 3 + 1 + 1 = 7 flowers.
There is 1 garden that is complete.
The minimum number of flowers in the incomplete gardens is 2.
Thus, the total beauty is 1 * 12 + 2 * 1 = 12 + 2 = 14.
No other way of planting flowers can obtain a total beauty higher than 14.
Example 2:
Input: flowers = [2,4,5,3], newFlowers = 10, target = 5, full = 2, partial = 6
Output: 30
Explanation: Alice can plant
3 flowers in the 0th garden
0 flowers in the 1st garden
0 flowers in the 2nd garden
2 flowers in the 3rd garden
The gardens will then be [5,4,5,5]. She planted a total of 3 + 0 + 0 + 2 = 5 flowers.
There are 3 gardens that are complete.
The minimum number of flowers in the incomplete gardens is 4.
Thus, the total beauty is 3 * 2 + 4 * 6 = 6 + 24 = 30.
No other way of planting flowers can obtain a total beauty higher than 30.
Note that Alice could make all the gardens complete but in this case, she would obtain a lower total beauty.
Constraints:
1 <= flowers.length <= 105
1 <= flowers[i], target <= 105
1 <= newFlowers <= 1010
1 <= full, partial <= 105
Constructor and Description |
---|
Solution() |
Modifier and Type | Method and Description |
---|---|
long |
maximumBeauty(int[] flowers,
long newFlowers,
int target,
int full,
int partial) |
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