Class Solution
- java.lang.Object
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- g1401_1500.s1473_paint_house_iii.Solution
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public class Solution extends Object
1473 - Paint House III.Hard
There is a row of
mhouses in a small city, each house must be painted with one of thencolors (labeled from1ton), some houses that have been painted last summer should not be painted again.A neighborhood is a maximal group of continuous houses that are painted with the same color.
- For example:
houses = [1,2,2,3,3,2,1,1]contains5neighborhoods[{1}, {2,2}, {3,3}, {2}, {1,1}].
Given an array
houses, anm x nmatrixcostand an integertargetwhere:houses[i]: is the color of the housei, and0if the house is not painted yet.cost[i][j]: is the cost of paint the houseiwith the colorj + 1.
Return the minimum cost of painting all the remaining houses in such a way that there are exactly
targetneighborhoods. If it is not possible, return-1.Example 1:
Input: houses = [0,0,0,0,0], cost = [[1,10],[10,1],[10,1],[1,10],[5,1]], m = 5, n = 2, target = 3
Output: 9
Explanation: Paint houses of this way [1,2,2,1,1]
This array contains target = 3 neighborhoods, [{1}, {2,2}, {1,1}].
Cost of paint all houses (1 + 1 + 1 + 1 + 5) = 9.
Example 2:
Input: houses = [0,2,1,2,0], cost = [[1,10],[10,1],[10,1],[1,10],[5,1]], m = 5, n = 2, target = 3
Output: 11
Explanation: Some houses are already painted, Paint the houses of this way [2,2,1,2,2]
This array contains target = 3 neighborhoods, [{2,2}, {1}, {2,2}].
Cost of paint the first and last house (10 + 1) = 11.
Example 3:
Input: houses = [3,1,2,3], cost = [[1,1,1],[1,1,1],[1,1,1],[1,1,1]], m = 4, n = 3, target = 3
Output: -1
Explanation: Houses are already painted with a total of 4 neighborhoods [{3},{1},{2},{3}] different of target = 3.
Constraints:
m == houses.length == cost.lengthn == cost[i].length1 <= m <= 1001 <= n <= 201 <= target <= m0 <= houses[i] <= n1 <= cost[i][j] <= 104
- For example:
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description intminCost(int[] houses, int[][] cost, int nColors, int tGroups)
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