Class Solution
- java.lang.Object
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- g0801_0900.s0898_bitwise_ors_of_subarrays.Solution
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public class Solution extends Object
898 - Bitwise ORs of Subarrays.Medium
We have an array
arr
of non-negative integers.For every (contiguous) subarray
sub = [arr[i], arr[i + 1], ..., arr[j]]
(withi <= j
), we take the bitwise OR of all the elements insub
, obtaining a resultarr[i] | arr[i + 1] | ... | arr[j]
.Return the number of possible results. Results that occur more than once are only counted once in the final answer
Example 1:
Input: arr = [0]
Output: 1
Explanation: There is only one possible result: 0.
Example 2:
Input: arr = [1,1,2]
Output: 3
Explanation:
The possible subarrays are [1], [1], [2], [1, 1], [1, 2], [1, 1, 2]. These yield the results 1, 1, 2, 1, 3, 3. There are 3 unique values, so the answer is 3.
Example 3:
Input: arr = [1,2,4]
Output: 6
Explanation: The possible results are 1, 2, 3, 4, 6, and 7.
Constraints:
1 <= nums.length <= 5 * 104
0 <= nums[i] <= 109
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description int
subarrayBitwiseORs(int[] arr)
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