Class Solution


  • public class Solution
    extends Object
    898 - Bitwise ORs of Subarrays.

    Medium

    We have an array arr of non-negative integers.

    For every (contiguous) subarray sub = [arr[i], arr[i + 1], ..., arr[j]] (with i <= j), we take the bitwise OR of all the elements in sub, obtaining a result arr[i] | arr[i + 1] | ... | arr[j].

    Return the number of possible results. Results that occur more than once are only counted once in the final answer

    Example 1:

    Input: arr = [0]

    Output: 1

    Explanation: There is only one possible result: 0.

    Example 2:

    Input: arr = [1,1,2]

    Output: 3

    Explanation:

     The possible subarrays are [1], [1], [2], [1, 1], [1, 2], [1, 1, 2].
     These yield the results 1, 1, 2, 1, 3, 3.
     There are 3 unique values, so the answer is 3. 
    

    Example 3:

    Input: arr = [1,2,4]

    Output: 6

    Explanation: The possible results are 1, 2, 3, 4, 6, and 7.

    Constraints:

    • 1 <= nums.length <= 5 * 104
    • 0 <= nums[i] <= 109
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • subarrayBitwiseORs

        public int subarrayBitwiseORs​(int[] arr)