Class Solution


  • public class Solution
    extends Object
    1862 - Sum of Floored Pairs.

    Hard

    Given an integer array nums, return the sum of floor(nums[i] / nums[j]) for all pairs of indices 0 <= i, j < nums.length in the array. Since the answer may be too large, return it modulo 109 + 7.

    The floor() function returns the integer part of the division.

    Example 1:

    Input: nums = [2,5,9]

    Output: 10

    Explanation:

    floor(2 / 5) = floor(2 / 9) = floor(5 / 9) = 0

    floor(2 / 2) = floor(5 / 5) = floor(9 / 9) = 1

    floor(5 / 2) = 2

    floor(9 / 2) = 4

    floor(9 / 5) = 1

    We calculate the floor of the division for every pair of indices in the array then sum them up.

    Example 2:

    Input: nums = [7,7,7,7,7,7,7]

    Output: 49

    Constraints:

    • 1 <= nums.length <= 105
    • 1 <= nums[i] <= 105
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • sumOfFlooredPairs

        public int sumOfFlooredPairs​(int[] nums)