Class Solution


  • public class Solution
    extends Object
    1962 - Remove Stones to Minimize the Total.

    Medium

    You are given a 0-indexed integer array piles, where piles[i] represents the number of stones in the ith pile, and an integer k. You should apply the following operation exactly k times:

    • Choose any piles[i] and remove floor(piles[i] / 2) stones from it.

    Notice that you can apply the operation on the same pile more than once.

    Return the minimum possible total number of stones remaining after applying the k operations.

    floor(x) is the greatest integer that is smaller than or equal to x (i.e., rounds x down).

    Example 1:

    Input: piles = [5,4,9], k = 2

    Output: 12

    Explanation: Steps of a possible scenario are:

    • Apply the operation on pile 2. The resulting piles are [5,4,5].

    • Apply the operation on pile 0. The resulting piles are [3,4,5].

    The total number of stones in [3,4,5] is 12.

    Example 2:

    Input: piles = [4,3,6,7], k = 3

    Output: 12

    Explanation: Steps of a possible scenario are:

    • Apply the operation on pile 2. The resulting piles are [4,3,3,7].

    • Apply the operation on pile 3. The resulting piles are [4,3,3,4].

    • Apply the operation on pile 0. The resulting piles are [2,3,3,4].

    The total number of stones in [2,3,3,4] is 12.

    Constraints:

    • 1 <= piles.length <= 105
    • 1 <= piles[i] <= 104
    • 1 <= k <= 105
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • minStoneSum

        public int minStoneSum​(int[] piles,
                               int k)