Class Solution


  • public class Solution
    extends Object
    1995 - Count Special Quadruplets.

    Easy

    Given a 0-indexed integer array nums, return the number of distinct quadruplets (a, b, c, d) such that:

    • nums[a] + nums[b] + nums[c] == nums[d], and
    • a < b < c < d

    Example 1:

    Input: nums = [1,2,3,6]

    Output: 1

    Explanation: The only quadruplet that satisfies the requirement is (0, 1, 2, 3) because 1 + 2 + 3 == 6.

    Example 2:

    Input: nums = [3,3,6,4,5]

    Output: 0

    Explanation: There are no such quadruplets in [3,3,6,4,5].

    Example 3:

    Input: nums = [1,1,1,3,5]

    Output: 4

    Explanation: The 4 quadruplets that satisfy the requirement are:

    • (0, 1, 2, 3): 1 + 1 + 1 == 3

    • (0, 1, 3, 4): 1 + 1 + 3 == 5

    • (0, 2, 3, 4): 1 + 1 + 3 == 5

    • (1, 2, 3, 4): 1 + 1 + 3 == 5

    Constraints:

    • 4 <= nums.length <= 50
    • 1 <= nums[i] <= 100
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • countQuadruplets

        public int countQuadruplets​(int[] nums)