Class Solution
- java.lang.Object
-
- g2101_2200.s2105_watering_plants_ii.Solution
-
public class Solution extends Object
2105 - Watering Plants II.Medium
Alice and Bob want to water
n
plants in their garden. The plants are arranged in a row and are labeled from0
ton - 1
from left to right where theith
plant is located atx = i
.Each plant needs a specific amount of water. Alice and Bob have a watering can each, initially full. They water the plants in the following way:
- Alice waters the plants in order from left to right , starting from the
0th
plant. Bob waters the plants in order from right to left , starting from the(n - 1)th
plant. They begin watering the plants simultaneously. - It takes the same amount of time to water each plant regardless of how much water it needs.
- Alice/Bob must water the plant if they have enough in their can to fully water it. Otherwise, they first refill their can (instantaneously) then water the plant.
- In case both Alice and Bob reach the same plant, the one with more water currently in his/her watering can should water this plant. If they have the same amount of water, then Alice should water this plant.
Given a 0-indexed integer array
plants
ofn
integers, whereplants[i]
is the amount of water theith
plant needs, and two integerscapacityA
andcapacityB
representing the capacities of Alice’s and Bob’s watering cans respectively, return the number of times they have to refill to water all the plants.Example 1:
Input: plants = [2,2,3,3], capacityA = 5, capacityB = 5
Output: 1
Explanation:
-
Initially, Alice and Bob have 5 units of water each in their watering cans.
-
Alice waters plant 0, Bob waters plant 3.
-
Alice and Bob now have 3 units and 2 units of water respectively.
-
Alice has enough water for plant 1, so she waters it. Bob does not have enough water for plant 2, so he refills his can then waters it.
So, the total number of times they have to refill to water all the plants is 0 + 0 + 1 + 0 = 1.
Example 2:
Input: plants = [2,2,3,3], capacityA = 3, capacityB = 4
Output: 2
Explanation:
-
Initially, Alice and Bob have 3 units and 4 units of water in their watering cans respectively.
-
Alice waters plant 0, Bob waters plant 3.
-
Alice and Bob now have 1 unit of water each, and need to water plants 1 and 2 respectively.
-
Since neither of them have enough water for their current plants, they refill their cans and then water the plants.
So, the total number of times they have to refill to water all the plants is 0 + 1 + 1 + 0 = 2.
Example 3:
Input: plants = [5], capacityA = 10, capacityB = 8
Output: 0
Explanation:
-
There is only one plant.
-
Alice’s watering can has 10 units of water, whereas Bob’s can has 8 units. Since Alice has more water in her can, she waters this plant.
So, the total number of times they have to refill is 0.
Constraints:
n == plants.length
1 <= n <= 105
1 <= plants[i] <= 106
max(plants[i]) <= capacityA, capacityB <= 109
- Alice waters the plants in order from left to right , starting from the
-
-
Constructor Summary
Constructors Constructor Description Solution()
-
Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description int
minimumRefill(int[] plants, int capacityA, int capacityB)
-