Class Solution
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- g2301_2400.s2317_maximum_xor_after_operations.Solution
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public class Solution extends Object
2317 - Maximum XOR After Operations.Medium
You are given a 0-indexed integer array
nums. In one operation, select any non-negative integerxand an indexi, then updatenums[i]to be equal tonums[i] AND (nums[i] XOR x).Note that
ANDis the bitwise AND operation andXORis the bitwise XOR operation.Return the maximum possible bitwise XOR of all elements of
numsafter applying the operation any number of times.Example 1:
Input: nums = [3,2,4,6]
Output: 7
Explanation: Apply the operation with x = 4 and i = 3, num[3] = 6 AND (6 XOR 4) = 6 AND 2 = 2.
Now, nums = [3, 2, 4, 2] and the bitwise XOR of all the elements = 3 XOR 2 XOR 4 XOR 2 = 7.
It can be shown that 7 is the maximum possible bitwise XOR.
Note that other operations may be used to achieve a bitwise XOR of 7.
Example 2:
Input: nums = [1,2,3,9,2]
Output: 11
Explanation: Apply the operation zero times.
The bitwise XOR of all the elements = 1 XOR 2 XOR 3 XOR 9 XOR 2 = 11.
It can be shown that 11 is the maximum possible bitwise XOR.
Constraints:
1 <= nums.length <= 1050 <= nums[i] <= 108
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description intmaximumXOR(int[] nums)
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