Package g0001_0100.s0079_word_search
Class Solution
- java.lang.Object
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- g0001_0100.s0079_word_search.Solution
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public class Solution extends Object
79 - Word Search.Medium
Given an
m x ngrid of charactersboardand a stringword, returntrueifwordexists in the grid.The word can be constructed from letters of sequentially adjacent cells, where adjacent cells are horizontally or vertically neighboring. The same letter cell may not be used more than once.
Example 1:

Input: board = [[“A”,“B”,“C”,“E”],[“S”,“F”,“C”,“S”],[“A”,“D”,“E”,“E”]], word = “ABCCED”
Output: true
Example 2:

Input: board = [[“A”,“B”,“C”,“E”],[“S”,“F”,“C”,“S”],[“A”,“D”,“E”,“E”]], word = “SEE”
Output: true
Example 3:

Input: board = [[“A”,“B”,“C”,“E”],[“S”,“F”,“C”,“S”],[“A”,“D”,“E”,“E”]], word = “ABCB”
Output: false
Constraints:
m == board.lengthn = board[i].length1 <= m, n <= 61 <= word.length <= 15boardandwordconsists of only lowercase and uppercase English letters.
Follow up: Could you use search pruning to make your solution faster with a larger
board?
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Constructor Summary
Constructors Constructor Description Solution()
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Method Detail
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exist
public boolean exist(char[][] board, String word)
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