Solution (leetcode-in-java 1.23 API)

java.lang.Object
- g0601_0700.s0674_longest_continuous_increasing_subsequence.Solution

```
public class Solution
extends Object
```
674 - Longest Continuous Increasing Subsequence.
Easy

Given an unsorted array of integers nums, return the length of the longest continuous increasing subsequence (i.e. subarray). The subsequence must be strictly increasing.

A continuous increasing subsequence is defined by two indices l and r (l < r) such that it is [nums[l], nums[l + 1], ..., nums[r - 1], nums[r]] and for each l <= i < r, nums[i] < nums[i + 1].

Example 1:

Input: nums = [1,3,5,4,7]

Output: 3

Explanation: The longest continuous increasing subsequence is [1,3,5] with length 3. Even though [1,3,5,7] is an increasing subsequence, it is not continuous as elements 5 and 7 are separated by element 4.

Example 2:

Input: nums = [2,2,2,2,2]

Output: 1

Explanation: The longest continuous increasing subsequence is [2] with length 1. Note that it must be strictly increasing.

Constraints:
- 1 <= nums.length <= 10⁴
- -10⁹ <= nums[i] <= 10⁹

- Constructor Summary
  
  Constructors
  Constructor Description
  
  Solution()
- Method Summary
  
  All Methods Instance Methods Concrete Methods
  Modifier and Type Method Description
  
  int findLengthOfLCIS(int[] nums)
  - Methods inherited from class java.lang.Object
    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Detail
- Solution
```
public Solution()
```

Method Detail

findLengthOfLCIS

public int findLengthOfLCIS(int[] nums)