Class Solution
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- g0701_0800.s0785_is_graph_bipartite.Solution
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public class Solution extends Object
785 - Is Graph Bipartite?.
Medium
There is an undirected graph with
nnodes, where each node is numbered between0andn - 1. You are given a 2D arraygraph, wheregraph[u]is an array of nodes that nodeuis adjacent to. More formally, for eachvingraph[u], there is an undirected edge between nodeuand nodev. The graph has the following properties:- There are no self-edges (
graph[u]does not containu). - There are no parallel edges (
graph[u]does not contain duplicate values). - If
vis ingraph[u], thenuis ingraph[v](the graph is undirected). - The graph may not be connected, meaning there may be two nodes
uandvsuch that there is no path between them.
A graph is bipartite if the nodes can be partitioned into two independent sets
AandBsuch that every edge in the graph connects a node in setAand a node in setB.Return
trueif and only if it is bipartite.Example 1:

Input: graph = [[1,2,3],[0,2],[0,1,3],[0,2]]
Output: false
Explanation: There is no way to partition the nodes into two independent sets such that every edge connects a node in one and a node in the other.
Example 2:

Input: graph = [[1,3],[0,2],[1,3],[0,2]]
Output: true
Explanation: We can partition the nodes into two sets: {0, 2} and {1, 3}.
Constraints:
graph.length == n1 <= n <= 1000 <= graph[u].length < n0 <= graph[u][i] <= n - 1graph[u]does not containu.- All the values of
graph[u]are unique. - If
graph[u]containsv, thengraph[v]containsu.
- There are no self-edges (
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description booleanisBipartite(int[][] graph)
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