Class Solution


  • public class Solution
    extends Object
    1043 - Partition Array for Maximum Sum.

    Medium

    Given an integer array arr, partition the array into (contiguous) subarrays of length at most k. After partitioning, each subarray has their values changed to become the maximum value of that subarray.

    Return the largest sum of the given array after partitioning. Test cases are generated so that the answer fits in a 32-bit integer.

    Example 1:

    Input: arr = [1,15,7,9,2,5,10], k = 3

    Output: 84

    Explanation: arr becomes [15,15,15,9,10,10,10]

    Example 2:

    Input: arr = [1,4,1,5,7,3,6,1,9,9,3], k = 4

    Output: 83

    Example 3:

    Input: arr = [1], k = 1

    Output: 1

    Constraints:

    • 1 <= arr.length <= 500
    • 0 <= arr[i] <= 109
    • 1 <= k <= arr.length
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • maxSumAfterPartitioning

        public int maxSumAfterPartitioning​(int[] arr,
                                           int k)