Class Solution
- java.lang.Object
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- g1401_1500.s1401_circle_and_rectangle_overlapping.Solution
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public class Solution extends Object
1401 - Circle and Rectangle Overlapping.Medium
You are given a circle represented as
(radius, xCenter, yCenter)and an axis-aligned rectangle represented as(x1, y1, x2, y2), where(x1, y1)are the coordinates of the bottom-left corner, and(x2, y2)are the coordinates of the top-right corner of the rectangle.Return
trueif the circle and rectangle are overlapped otherwise returnfalse. In other words, check if there is any point(xi, yi)that belongs to the circle and the rectangle at the same time.Example 1:

Input: radius = 1, xCenter = 0, yCenter = 0, x1 = 1, y1 = -1, x2 = 3, y2 = 1
Output: true
Explanation: Circle and rectangle share the point (1,0).
Example 2:
Input: radius = 1, xCenter = 1, yCenter = 1, x1 = 1, y1 = -3, x2 = 2, y2 = -1
Output: false
Example 3:

Input: radius = 1, xCenter = 0, yCenter = 0, x1 = -1, y1 = 0, x2 = 0, y2 = 1
Output: true
Constraints:
1 <= radius <= 2000-104 <= xCenter, yCenter <= 104-104 <= x1 < x2 <= 104-104 <= y1 < y2 <= 104
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description booleancheckOverlap(int radius, int xCenter, int yCenter, int x1, int y1, int x2, int y2)
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