Solution (leetcode-in-java 1.23 API)

java.lang.Object
- g1701_1800.s1800_maximum_ascending_subarray_sum.Solution

```
public class Solution
extends Object
```
1800 - Maximum Ascending Subarray Sum.
Easy

Given an array of positive integers nums, return the maximum possible sum of an ascending subarray in nums.

A subarray is defined as a contiguous sequence of numbers in an array.

A subarray [nums_l, nums_l+1, …, nums_r-1, nums_r] is ascending if for all i where l <= i < r, nums_i < nums_i+1. Note that a subarray of size 1 is ascending.

Example 1:

Input: nums = [10,20,30,5,10,50]

Output: 65

Explanation: [5,10,50] is the ascending subarray with the maximum sum of 65.

Example 2:

Input: nums = [10,20,30,40,50]

Output: 150

Explanation: [10,20,30,40,50] is the ascending subarray with the maximum sum of 150.

Example 3:

Input: nums = [12,17,15,13,10,11,12]

Output: 33

Explanation: [10,11,12] is the ascending subarray with the maximum sum of 33.

Constraints:
- 1 <= nums.length <= 100
- 1 <= nums[i] <= 100

- Constructor Summary
  
  Constructors
  Constructor Description
  
  Solution()
- Method Summary
  
  All Methods Instance Methods Concrete Methods
  Modifier and Type Method Description
  
  int maxAscendingSum(int[] nums)
  - Methods inherited from class java.lang.Object
    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Detail
- Solution
```
public Solution()
```

Method Detail

maxAscendingSum

public int maxAscendingSum(int[] nums)