Class Solution
- java.lang.Object
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- g2001_2100.s2018_check_if_word_can_be_placed_in_crossword.Solution
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public class Solution extends Object
2018 - Check if Word Can Be Placed In Crossword.Medium
You are given an
m x n
matrixboard
, representing the current state of a crossword puzzle. The crossword contains lowercase English letters (from solved words),' '
to represent any empty cells, and'#'
to represent any blocked cells.A word can be placed horizontally (left to right or right to left) or vertically (top to bottom or bottom to top) in the board if:
- It does not occupy a cell containing the character
'#'
. - The cell each letter is placed in must either be
' '
(empty) or match the letter already on theboard
. - There must not be any empty cells
' '
or other lowercase letters directly left or right of the word if the word was placed horizontally. - There must not be any empty cells
' '
or other lowercase letters directly above or below the word if the word was placed vertically.
Given a string
word
, returntrue
ifword
can be placed inboard
, orfalse
otherwise.Example 1:
Input: board = [[“#”, " ", “#”], [" ", " ", “#”], [“#”, “c”, " "]], word = “abc”
Output: true
Explanation: The word “abc” can be placed as shown above (top to bottom).
Example 2:
Input: board = [[" ", “#”, “a”], [" ", “#”, “c”], [" ", “#”, “a”]], word = “ac”
Output: false
Explanation: It is impossible to place the word because there will always be a space/letter above or below it.
Example 3:
Input: board = [[“#”, " ", “#”], [" ", " ", “#”], [“#”, " ", “c”]], word = “ca”
Output: true
Explanation: The word “ca” can be placed as shown above (right to left).
Constraints:
m == board.length
n == board[i].length
1 <= m * n <= 2 * 105
board[i][j]
will be' '
,'#'
, or a lowercase English letter.1 <= word.length <= max(m, n)
word
will contain only lowercase English letters.
- It does not occupy a cell containing the character
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Constructor Summary
Constructors Constructor Description Solution()
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Method Detail
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placeWordInCrossword
public boolean placeWordInCrossword(char[][] board, String word)
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