Class Solution
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- g2001_2100.s2055_plates_between_candles.Solution
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public class Solution extends Object
2055 - Plates Between Candles.Medium
There is a long table with a line of plates and candles arranged on top of it. You are given a 0-indexed string
sconsisting of characters'*'and'|'only, where a'*'represents a plate and a'|'represents a candle.You are also given a 0-indexed 2D integer array
querieswherequeries[i] = [lefti, righti]denotes the substrings[lefti…righti]( inclusive ). For each query, you need to find the number of plates between candles that are in the substring. A plate is considered between candles if there is at least one candle to its left and at least one candle to its right in the substring.- For example,
s = "||**||**|*", and a query[3, 8]denotes the substring"*||******|". The number of plates between candles in this substring is2, as each of the two plates has at least one candle in the substring to its left and right.
Return an integer array
answerwhereanswer[i]is the answer to theithquery.Example 1:

Input: s = “**|**|***|”, queries = [[2,5],[5,9]]
Output: [2,3]
Explanation: - queries[0] has two plates between candles. - queries[1] has three plates between candles.
Example 2:

Input: s = “***|**|*****|**||**|*”, queries = [[1,17],[4,5],[14,17],[5,11],[15,16]]
Output: [9,0,0,0,0]
Explanation: - queries[0] has nine plates between candles. - The other queries have zero plates between candles.
Constraints:
3 <= s.length <= 105sconsists of'*'and'|'characters.1 <= queries.length <= 105queries[i].length == 20 <= lefti <= righti < s.length
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Constructor Summary
Constructors Constructor Description Solution()
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Method Detail
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platesBetweenCandles
public int[] platesBetweenCandles(String s, int[][] queries)
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