Solution (leetcode-in-java 1.23 API)

java.lang.Object
- g2201_2300.s2278_percentage_of_letter_in_string.Solution

```
public class Solution
extends Object
```
2278 - Percentage of Letter in String.
Easy

Given a string s and a character letter, return the percentage of characters in s that equal letter rounded down to the nearest whole percent.

Example 1:

Input: s = “foobar”, letter = “o”

Output: 33

Explanation:

The percentage of characters in s that equal the letter ‘o’ is 2 / 6 * 100% = 33% when rounded down, so we return 33.

Example 2:

Input: s = “jjjj”, letter = “k”

Output: 0

Explanation:

The percentage of characters in s that equal the letter ‘k’ is 0%, so we return 0.

Constraints:
- 1 <= s.length <= 100
- s consists of lowercase English letters.
- letter is a lowercase English letter.

- Constructor Summary
  
  Constructors
  Constructor Description
  
  Solution()
- Method Summary
  
  All Methods Instance Methods Concrete Methods
  Modifier and Type Method Description
  
  int percentageLetter(String s, char letter)
  - Methods inherited from class java.lang.Object
    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Detail
- Solution
```
public Solution()
```

Method Detail

percentageLetter

public int percentageLetter(String s,
                            char letter)