Class Solution


  • public class Solution
    extends Object
    2558 - Take Gifts From the Richest Pile.

    Easy

    You are given an integer array gifts denoting the number of gifts in various piles. Every second, you do the following:

    • Choose the pile with the maximum number of gifts.
    • If there is more than one pile with the maximum number of gifts, choose any.
    • Leave behind the floor of the square root of the number of gifts in the pile. Take the rest of the gifts.

    Return the number of gifts remaining after k seconds.

    Example 1:

    Input: gifts = [25,64,9,4,100], k = 4

    Output: 29

    Explanation: The gifts are taken in the following way:

    • In the first second, the last pile is chosen and 10 gifts are left behind.
    • Then the second pile is chosen and 8 gifts are left behind.
    • After that the first pile is chosen and 5 gifts are left behind.
    • Finally, the last pile is chosen again and 3 gifts are left behind.

    The final remaining gifts are [5,8,9,4,3], so the total number of gifts remaining is 29.

    Example 2:

    Input: gifts = [1,1,1,1], k = 4

    Output: 4

    Explanation:

    In this case, regardless which pile you choose, you have to leave behind 1 gift in each pile.

    That is, you can’t take any pile with you.

    So, the total gifts remaining are 4.

    Constraints:

    • 1 <= gifts.length <= 103
    • 1 <= gifts[i] <= 109
    • 1 <= k <= 103
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • pickGifts

        public long pickGifts​(int[] gifts,
                              int k)