java.lang.Object
g2401_2500.s2460_apply_operations_to_an_array.Solution

public class Solution extends Object
2460 - Apply Operations to an Array.

Easy

You are given a 0-indexed array nums of size n consisting of non-negative integers.

You need to apply n - 1 operations to this array where, in the ith operation ( 0-indexed ), you will apply the following on the ith element of nums:

  • If nums[i] == nums[i + 1], then multiply nums[i] by 2 and set nums[i + 1] to 0. Otherwise, you skip this operation.

After performing all the operations, shift all the 0’s to the end of the array.

  • For example, the array [1,0,2,0,0,1] after shifting all its 0’s to the end, is [1,2,1,0,0,0].

Return the resulting array.

Note that the operations are applied sequentially , not all at once.

Example 1:

Input: nums = [1,2,2,1,1,0]

Output: [1,4,2,0,0,0]

Explanation: We do the following operations:

  • i = 0: nums[0] and nums[1] are not equal, so we skip this operation.

  • i = 1: nums[1] and nums[2] are equal, we multiply nums[1] by 2 and change nums[2] to 0. The array becomes [1, 4 , 0 ,1,1,0].

  • i = 2: nums[2] and nums[3] are not equal, so we skip this operation.

  • i = 3: nums[3] and nums[4] are equal, we multiply nums[3] by 2 and change nums[4] to 0. The array becomes [1,4,0, 2 , 0 ,0].

  • i = 4: nums[4] and nums[5] are equal, we multiply nums[4] by 2 and change nums[5] to 0. The array becomes [1,4,0,2, 0 , 0 ].

After that, we shift the 0’s to the end, which gives the array [1,4,2,0,0,0].

Example 2:

Input: nums = [0,1]

Output: [1,0]

Explanation: No operation can be applied, we just shift the 0 to the end.

Constraints:

  • 2 <= nums.length <= 2000
  • 0 <= nums[i] <= 1000
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • applyOperations

      public int[] applyOperations(int[] nums)