java.lang.Object
g3601_3700.s3612_process_string_with_special_operations_i.Solution

public class Solution extends Object
3612 - Process String with Special Operations I.

Medium

You are given a string s consisting of lowercase English letters and the special characters: *, #, and %.

Build a new string result by processing s according to the following rules from left to right:

  • If the letter is a lowercase English letter append it to result.
  • A '*' removes the last character from result, if it exists.
  • A '#' duplicates the current result and appends it to itself.
  • A '%' reverses the current result.

Return the final string result after processing all characters in s.

Example 1:

Input: s = “a#b%*”

Output: “ba”

Explanation:

is[i]OperationCurrent result
0'a'Append 'a'"a"
1'#'Duplicate result"aa"
2'b'Append 'b'"aab"
3'%'Reverse result"baa"
4'*'Remove the last character"ba"

Thus, the final result is "ba".

Example 2:

Input: s = “z*#”

Output: ""

Explanation:

is[i]OperationCurrent result
0'z'Append 'z'"z"
1'*'Remove the last character""
2'#'Duplicate the string""

Thus, the final result is "".

Constraints:

  • 1 <= s.length <= 20
  • s consists of only lowercase English letters and special characters *, #, and %.
  • Constructor Details

    • Solution

      public Solution()
  • Method Details