Class Solution
Easy
There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9.
You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where:
- The first character of the
ithpair denotes theithring’s color ('R','G','B'). - The second character of the
ithpair denotes the rod that theithring is placed on ('0'to'9').
For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1.
Return the number of rods that have all three colors of rings on them.
Example 1:

Input: rings = “B0B6G0R6R0R6G9”
Output: 1
Explanation:
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The rod labeled 0 holds 3 rings with all colors: red, green, and blue.
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The rod labeled 6 holds 3 rings, but it only has red and blue.
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The rod labeled 9 holds only a green ring.
Thus, the number of rods with all three colors is 1.
Example 2:

Input: rings = “B0R0G0R9R0B0G0”
Output: 1
Explanation:
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The rod labeled 0 holds 6 rings with all colors: red, green, and blue.
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The rod labeled 9 holds only a red ring.
Thus, the number of rods with all three colors is 1.
Example 3:
Input: rings = “G4”
Output: 0
Explanation: Only one ring is given. Thus, no rods have all three colors.
Constraints:
rings.length == 2 * n1 <= n <= 100rings[i]whereiis even is either'R','G', or'B'( 0-indexed ).rings[i]whereiis odd is a digit from'0'to'9'( 0-indexed ).
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Constructor Summary
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Method Summary
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Constructor Details
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Solution
public Solution()
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Method Details
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countPoints
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