Class Solution


  • public class Solution
    extends Object
    813 - Largest Sum of Averages\. Medium You are given an integer array `nums` and an integer `k`. You can partition the array into **at most** `k` non-empty adjacent subarrays. The **score** of a partition is the sum of the averages of each subarray. Note that the partition must use every integer in `nums`, and that the score is not necessarily an integer. Return _the maximum **score** you can achieve of all the possible partitions_. Answers within 10-6 of the actual answer will be accepted. **Example 1:** **Input:** nums = [9,1,2,3,9], k = 3 **Output:** 20.00000 **Explanation:** The best choice is to partition nums into [9], [1, 2, 3], [9]. The answer is 9 + (1 + 2 + 3) / 3 + 9 = 20. We could have also partitioned nums into [9, 1], [2], [3, 9], for example. That partition would lead to a score of 5 + 2 + 6 = 13, which is worse. **Example 2:** **Input:** nums = [1,2,3,4,5,6,7], k = 4 **Output:** 20.50000 **Constraints:** * `1 <= nums.length <= 100` * 1 <= nums[i] <= 104 * `1 <= k <= nums.length`
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • largestSumOfAverages

        public double largestSumOfAverages​(int[] nums,
                                           int k)