Class Solution


  • public class Solution
    extends Object
    836 - Rectangle Overlap\. Easy An axis-aligned rectangle is represented as a list `[x1, y1, x2, y2]`, where `(x1, y1)` is the coordinate of its bottom-left corner, and `(x2, y2)` is the coordinate of its top-right corner. Its top and bottom edges are parallel to the X-axis, and its left and right edges are parallel to the Y-axis. Two rectangles overlap if the area of their intersection is **positive**. To be clear, two rectangles that only touch at the corner or edges do not overlap. Given two axis-aligned rectangles `rec1` and `rec2`, return `true` _if they overlap, otherwise return_ `false`. **Example 1:** **Input:** rec1 = [0,0,2,2], rec2 = [1,1,3,3] **Output:** true **Example 2:** **Input:** rec1 = [0,0,1,1], rec2 = [1,0,2,1] **Output:** false **Example 3:** **Input:** rec1 = [0,0,1,1], rec2 = [2,2,3,3] **Output:** false **Constraints:** * `rect1.length == 4` * `rect2.length == 4` * -109 <= rec1[i], rec2[i] <= 109 * `rec1` and `rec2` represent a valid rectangle with a non-zero area.
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • isRectangleOverlap

        public boolean isRectangleOverlap​(int[] rec1,
                                          int[] rec2)