Class TopVotedCandidate


  • public class TopVotedCandidate
    extends Object
    911 - Online Election\. Medium You are given two integer arrays `persons` and `times`. In an election, the ith vote was cast for `persons[i]` at time `times[i]`. For each query at a time `t`, find the person that was leading the election at time `t`. Votes cast at time `t` will count towards our query. In the case of a tie, the most recent vote (among tied candidates) wins. Implement the `TopVotedCandidate` class: * `TopVotedCandidate(int[] persons, int[] times)` Initializes the object with the `persons` and `times` arrays. * `int q(int t)` Returns the number of the person that was leading the election at time `t` according to the mentioned rules. **Example 1:** **Input** ["TopVotedCandidate", "q", "q", "q", "q", "q", "q"] [[[0, 1, 1, 0, 0, 1, 0], [0, 5, 10, 15, 20, 25, 30]], [3], [12], [25], [15], [24], [8]] **Output:** [null, 0, 1, 1, 0, 0, 1] **Explanation:** TopVotedCandidate topVotedCandidate = new TopVotedCandidate([0, 1, 1, 0, 0, 1, 0], [0, 5, 10, 15, 20, 25, 30]); topVotedCandidate.q(3); // return 0, At time 3, the votes are [0], and 0 is leading. topVotedCandidate.q(12); // return 1, At time 12, the votes are [0,1,1], and 1 is leading. topVotedCandidate.q(25); // return 1, At time 25, the votes are [0,1,1,0,0,1], and 1 is leading (as ties go to the most recent vote.) topVotedCandidate.q(15); // return 0 topVotedCandidate.q(24); // return 0 topVotedCandidate.q(8); // return 1 **Constraints:** * `1 <= persons.length <= 5000` * `times.length == persons.length` * `0 <= persons[i] < persons.length` * 0 <= times[i] <= 109 * `times` is sorted in a strictly increasing order. * times[0] <= t <= 109 * At most 104 calls will be made to `q`.
    • Constructor Detail

      • TopVotedCandidate

        public TopVotedCandidate​(int[] persons,
                                 int[] times)
    • Method Detail

      • q

        public int q​(int t)