Class Solution


  • public class Solution
    extends Object
    1675 - Minimize Deviation in Array\. Hard You are given an array `nums` of `n` positive integers. You can perform two types of operations on any element of the array any number of times: * If the element is **even** , **divide** it by `2`. * For example, if the array is `[1,2,3,4]`, then you can do this operation on the last element, and the array will be `[1,2,3,2].` * If the element is **odd** , **multiply** it by `2`. * For example, if the array is `[1,2,3,4]`, then you can do this operation on the first element, and the array will be `[2,2,3,4].` The **deviation** of the array is the **maximum difference** between any two elements in the array. Return _the **minimum deviation** the array can have after performing some number of operations._ **Example 1:** **Input:** nums = [1,2,3,4] **Output:** 1 **Explanation:** You can transform the array to [1,2,3,2], then to [2,2,3,2], then the deviation will be 3 - 2 = 1. **Example 2:** **Input:** nums = [4,1,5,20,3] **Output:** 3 **Explanation:** You can transform the array after two operations to [4,2,5,5,3], then the deviation will be 5 - 2 = 3. **Example 3:** **Input:** nums = [2,10,8] **Output:** 3 **Constraints:** * `n == nums.length` * 2 <= n <= 105 * 1 <= nums[i] <= 109
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • minimumDeviation

        public int minimumDeviation​(int[] nums)