Class Solution


  • public class Solution
    extends Object
    1727 - Largest Submatrix With Rearrangements\. Medium You are given a binary matrix `matrix` of size `m x n`, and you are allowed to rearrange the **columns** of the `matrix` in any order. Return _the area of the largest submatrix within_ `matrix` _where **every** element of the submatrix is_ `1` _after reordering the columns optimally._ **Example 1:** ![](https://assets.leetcode.com/uploads/2020/12/29/screenshot-2020-12-30-at-40536-pm.png) **Input:** matrix = \[\[0,0,1],[1,1,1],[1,0,1]] **Output:** 4 **Explanation:** You can rearrange the columns as shown above. The largest submatrix of 1s, in bold, has an area of 4. **Example 2:** ![](https://assets.leetcode.com/uploads/2020/12/29/screenshot-2020-12-30-at-40852-pm.png) **Input:** matrix = \[\[1,0,1,0,1]] **Output:** 3 **Explanation:** You can rearrange the columns as shown above. The largest submatrix of 1s, in bold, has an area of 3. **Example 3:** **Input:** matrix = \[\[1,1,0],[1,0,1]] **Output:** 2 **Explanation:** Notice that you must rearrange entire columns, and there is no way to make a submatrix of 1s larger than an area of 2. **Constraints:** * `m == matrix.length` * `n == matrix[i].length` * 1 <= m * n <= 105 * `matrix[i][j]` is either `0` or `1`.
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • largestSubmatrix

        public int largestSubmatrix​(int[][] matrix)