Class Solution


  • public class Solution
    extends Object
    1848 - Minimum Distance to the Target Element\. Easy Given an integer array `nums` **(0-indexed)** and two integers `target` and `start`, find an index `i` such that `nums[i] == target` and `abs(i - start)` is **minimized**. Note that `abs(x)` is the absolute value of `x`. Return `abs(i - start)`. It is **guaranteed** that `target` exists in `nums`. **Example 1:** **Input:** nums = [1,2,3,4,5], target = 5, start = 3 **Output:** 1 **Explanation:** nums[4] = 5 is the only value equal to target, so the answer is abs(4 - 3) = 1. **Example 2:** **Input:** nums = [1], target = 1, start = 0 **Output:** 0 **Explanation:** nums[0] = 1 is the only value equal to target, so the answer is abs(0 - 0) = 0. **Example 3:** **Input:** nums = [1,1,1,1,1,1,1,1,1,1], target = 1, start = 0 **Output:** 0 **Explanation:** Every value of nums is 1, but nums[0] minimizes abs(i - start), which is abs(0 - 0) = 0. **Constraints:** * `1 <= nums.length <= 1000` * 1 <= nums[i] <= 104 * `0 <= start < nums.length` * `target` is in `nums`.
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • getMinDistance

        public int getMinDistance​(int[] nums,
                                  int target,
                                  int start)