Class Solution
- java.lang.Object
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- g0501_0600.s0553_optimal_division.Solution
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public class Solution extends Object
553 - Optimal Division.Medium
You are given an integer array
nums
. The adjacent integers innums
will perform the float division.- For example, for
nums = [2,3,4]
, we will evaluate the expression"2/3/4"
.
However, you can add any number of parenthesis at any position to change the priority of operations. You want to add these parentheses such the value of the expression after the evaluation is maximum.
Return the corresponding expression that has the maximum value in string format.
Note: your expression should not contain redundant parenthesis.
Example 1:
Input: nums = [1000,100,10,2]
Output: “1000/(100/10/2)”
Explanation:
1000/(100/10/2) = 1000/((100/10)/2) = 200 However, the bold parenthesis in "1000/((100/10)/2)" are redundant, since they don't influence the operation priority. So you should return "1000/(100/10/2)". Other cases: 1000/(100/10)/2 = 50 1000/(100/(10/2)) = 50 1000/100/10/2 = 0.5 1000/100/(10/2) = 2
Example 2:
Input: nums = [2,3,4]
Output: “2/(3/4)”
Example 3:
Input: nums = [2]
Output: “2”
Constraints:
1 <= nums.length <= 10
2 <= nums[i] <= 1000
- There is only one optimal division for the given iput.
- For example, for
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Constructor Summary
Constructors Constructor Description Solution()
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Method Detail
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optimalDivision
public String optimalDivision(int[] nums)
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