Class Solution


  • public class Solution
    extends Object
    893 - Groups of Special-Equivalent Strings.

    Medium

    You are given an array of strings of the same length words.

    In one move , you can swap any two even indexed characters or any two odd indexed characters of a string words[i].

    Two strings words[i] and words[j] are special-equivalent if after any number of moves, words[i] == words[j].

    • For example, words[i] = "zzxy" and words[j] = "xyzz" are special-equivalent because we may make the moves "zzxy" -> "xzzy" -> "xyzz".

    A group of special-equivalent strings from words is a non-empty subset of words such that:

    • Every pair of strings in the group are special equivalent, and
    • The group is the largest size possible (i.e., there is not a string words[i] not in the group such that words[i] is special-equivalent to every string in the group).

    Return the number of groups of special-equivalent strings from words.

    Example 1:

    Input: words = [“abcd”,“cdab”,“cbad”,“xyzz”,“zzxy”,“zzyx”]

    Output: 3

    Explanation:

    One group is [“abcd”, “cdab”, “cbad”], since they are all pairwise special equivalent, and none of the other

    strings is all pairwise special equivalent to these.

    The other two groups are [“xyzz”, “zzxy”] and [“zzyx”].

    Note that in particular, “zzxy” is not special equivalent to “zzyx”.

    Example 2:

    Input: words = [“abc”,“acb”,“bac”,“bca”,“cab”,“cba”]

    Output: 3

    Constraints:

    • 1 <= words.length <= 1000
    • 1 <= words[i].length <= 20
    • words[i] consist of lowercase English letters.
    • All the strings are of the same length.
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • numSpecialEquivGroups

        public int numSpecialEquivGroups​(String[] words)