Class Solution


  • public class Solution
    extends Object
    1449 - Form Largest Integer With Digits That Add up to Target.

    Hard

    Given an array of integers cost and an integer target, return the maximum integer you can paint under the following rules:

    • The cost of painting a digit (i + 1) is given by cost[i] ( 0-indexed ).
    • The total cost used must be equal to target.
    • The integer does not have 0 digits.

    Since the answer may be very large, return it as a string. If there is no way to paint any integer given the condition, return "0".

    Example 1:

    Input: cost = [4,3,2,5,6,7,2,5,5], target = 9

    Output: “7772”

    Explanation: The cost to paint the digit ‘7’ is 2, and the digit ‘2’ is 3. Then cost(“7772”) = 2*3+ 3*1 = 9. You could also paint “977”, but “7772” is the largest number.

    Digit cost

    1 -> 4

    2 -> 3

    3 -> 2

    4 -> 5

    5 -> 6

    6 -> 7

    7 -> 2

    8 -> 5

    9 -> 5

    Example 2:

    Input: cost = [7,6,5,5,5,6,8,7,8], target = 12

    Output: “85”

    Explanation: The cost to paint the digit ‘8’ is 7, and the digit ‘5’ is 5. Then cost(“85”) = 7 + 5 = 12.

    Example 3:

    Input: cost = [2,4,6,2,4,6,4,4,4], target = 5

    Output: “0”

    Explanation: It is impossible to paint any integer with total cost equal to target.

    Constraints:

    • cost.length == 9
    • 1 <= cost[i], target <= 5000
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • largestNumber

        public String largestNumber​(int[] cost,
                                    int target)