Class Solution
- java.lang.Object
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- g1601_1700.s1652_defuse_the_bomb.Solution
-
public class Solution extends Object
1652 - Defuse the Bomb.Easy
You have a bomb to defuse, and your time is running out! Your informer will provide you with a circular array
code
of length ofn
and a keyk
.To decrypt the code, you must replace every number. All the numbers are replaced simultaneously.
- If
k > 0
, replace theith
number with the sum of the nextk
numbers. - If
k < 0
, replace theith
number with the sum of the previousk
numbers. - If
k == 0
, replace theith
number with0
.
As
code
is circular, the next element ofcode[n-1]
iscode[0]
, and the previous element ofcode[0]
iscode[n-1]
.Given the circular array
code
and an integer keyk
, return the decrypted code to defuse the bomb!Example 1:
Input: code = [5,7,1,4], k = 3
Output: [12,10,16,13]
Explanation: Each number is replaced by the sum of the next 3 numbers. The decrypted code is [7+1+4, 1+4+5, 4+5+7, 5+7+1]. Notice that the numbers wrap around.
Example 2:
Input: code = [1,2,3,4], k = 0
Output: [0,0,0,0]
Explanation: When k is zero, the numbers are replaced by 0.
Example 3:
Input: code = [2,4,9,3], k = -2
Output: [12,5,6,13]
Explanation: The decrypted code is [3+9, 2+3, 4+2, 9+4]. Notice that the numbers wrap around again. If k is negative, the sum is of the previous numbers.
Constraints:
n == code.length
1 <= n <= 100
1 <= code[i] <= 100
-(n - 1) <= k <= n - 1
- If
-
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Constructor Summary
Constructors Constructor Description Solution()
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