Class Solution
- java.lang.Object
-
- g1601_1700.s1680_concatenation_of_consecutive_binary_numbers.Solution
-
public class Solution extends Object
1680 - Concatenation of Consecutive Binary Numbers.Medium
Given an integer
n
, return the decimal value of the binary string formed by concatenating the binary representations of1
ton
in order, modulo109 + 7
.Example 1:
Input: n = 1
Output: 1
Explanation: “1” in binary corresponds to the decimal value 1.
Example 2:
Input: n = 3
Output: 27
Explanation: In binary, 1, 2, and 3 corresponds to “1”, “10”, and “11”.
After concatenating them, we have “11011”, which corresponds to the decimal value 27.
Example 3:
Input: n = 12
Output: 505379714
Explanation: The concatenation results in “1101110010111011110001001101010111100”.
The decimal value of that is 118505380540.
After modulo 109 + 7, the result is 505379714.
Constraints:
1 <= n <= 105
-
-
Constructor Summary
Constructors Constructor Description Solution()
-
Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description int
concatenatedBinary(int n)
-