Class Solution


  • public class Solution
    extends Object
    1752 - Check if Array Is Sorted and Rotated.

    Easy

    Given an array nums, return true if the array was originally sorted in non-decreasing order, then rotated some number of positions (including zero). Otherwise, return false.

    There may be duplicates in the original array.

    Note: An array A rotated by x positions results in an array B of the same length such that A[i] == B[(i+x) % A.length], where % is the modulo operation.

    Example 1:

    Input: nums = [3,4,5,1,2]

    Output: true

    Explanation: [1,2,3,4,5] is the original sorted array. You can rotate the array by x = 3 positions to begin on the the element of value 3: [3,4,5,1,2].

    Example 2:

    Input: nums = [2,1,3,4]

    Output: false

    Explanation: There is no sorted array once rotated that can make nums.

    Example 3:

    Input: nums = [1,2,3]

    Output: true

    Explanation: [1,2,3] is the original sorted array. You can rotate the array by x = 0 positions (i.e. no rotation) to make nums.

    Constraints:

    • 1 <= nums.length <= 100
    • 1 <= nums[i] <= 100
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • check

        public boolean check​(int[] nums)