Class Solution
- java.lang.Object
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- g1901_2000.s1945_sum_of_digits_of_string_after_convert.Solution
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public class Solution extends Object
1945 - Sum of Digits of String After Convert.Easy
You are given a string
s
consisting of lowercase English letters, and an integerk
.First, convert
s
into an integer by replacing each letter with its position in the alphabet (i.e., replace'a'
with1
,'b'
with2
, …,'z'
with26
). Then, transform the integer by replacing it with the sum of its digits. Repeat the transform operationk
times in total.For example, if
s = "zbax"
andk = 2
, then the resulting integer would be8
by the following operations:- Convert:
"zbax" \u279d "(26)(2)(1)(24)" \u279d "262124" \u279d 262124
- Transform #1:
262124 \u279d 2 + 6 + 2 + 1 + 2 + 4 \u279d 17
- Transform #2:
17 \u279d 1 + 7 \u279d 8
Return the resulting integer after performing the operations described above.
Example 1:
Input: s = “iiii”, k = 1
Output: 36
Explanation: The operations are as follows:
-
Convert: “iiii” \u279d “(9)(9)(9)(9)” \u279d “9999” \u279d 9999
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Transform #1: 9999 \u279d 9 + 9 + 9 + 9 \u279d 36 Thus the resulting integer is 36.
Example 2:
Input: s = “leetcode”, k = 2
Output: 6
Explanation: The operations are as follows:
-
Convert: “leetcode” \u279d “(12)(5)(5)(20)(3)(15)(4)(5)” \u279d “12552031545” \u279d 12552031545
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Transform #1: 12552031545 \u279d 1 + 2 + 5 + 5 + 2 + 0 + 3 + 1 + 5 + 4 + 5 \u279d 33
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Transform #2: 33 \u279d 3 + 3 \u279d 6 Thus the resulting integer is 6.
Example 3:
Input: s = “zbax”, k = 2
Output: 8
Constraints:
1 <= s.length <= 100
1 <= k <= 10
s
consists of lowercase English letters.
- Convert:
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Constructor Summary
Constructors Constructor Description Solution()
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Method Detail
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getLucky
public int getLucky(String s, int k)
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