Class Solution


  • public class Solution
    extends Object
    2342 - Max Sum of a Pair With Equal Sum of Digits.

    Medium

    You are given a 0-indexed array nums consisting of positive integers. You can choose two indices i and j, such that i != j, and the sum of digits of the number nums[i] is equal to that of nums[j].

    Return the maximum value of nums[i] + nums[j] that you can obtain over all possible indices i and j that satisfy the conditions.

    Example 1:

    Input: nums = [18,43,36,13,7]

    Output: 54

    Explanation: The pairs (i, j) that satisfy the conditions are:

    • (0, 2), both numbers have a sum of digits equal to 9, and their sum is 18 + 36 = 54.

    • (1, 4), both numbers have a sum of digits equal to 7, and their sum is 43 + 7 = 50.

    So the maximum sum that we can obtain is 54.

    Example 2:

    Input: nums = [10,12,19,14]

    Output: -1

    Explanation: There are no two numbers that satisfy the conditions, so we return -1.

    Constraints:

    • 1 <= nums.length <= 105
    • 1 <= nums[i] <= 109
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • maximumSum

        public int maximumSum​(int[] nums)