Class Solution


  • public class Solution
    extends Object
    2465 - Number of Distinct Averages.

    Easy

    You are given a 0-indexed integer array nums of even length.

    As long as nums is not empty, you must repetitively:

    • Find the minimum number in nums and remove it.
    • Find the maximum number in nums and remove it.
    • Calculate the average of the two removed numbers.

    The average of two numbers a and b is (a + b) / 2.

    • For example, the average of 2 and 3 is (2 + 3) / 2 = 2.5.

    Return the number of distinct averages calculated using the above process.

    Note that when there is a tie for a minimum or maximum number, any can be removed.

    Example 1:

    Input: nums = [4,1,4,0,3,5]

    Output: 2

    Explanation:

    1. Remove 0 and 5, and the average is (0 + 5) / 2 = 2.5. Now, nums = [4,1,4,3].

    2. Remove 1 and 4. The average is (1 + 4) / 2 = 2.5, and nums = [4,3].

    3. Remove 3 and 4, and the average is (3 + 4) / 2 = 3.5.

    Since there are 2 distinct numbers among 2.5, 2.5, and 3.5, we return 2.

    Example 2:

    Input: nums = [1,100]

    Output: 1

    Explanation:

    There is only one average to be calculated after removing 1 and 100, so we return 1.

    Constraints:

    • 2 <= nums.length <= 100
    • nums.length is even.
    • 0 <= nums[i] <= 100
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • distinctAverages

        public int distinctAverages​(int[] nums)