Class Solution
- java.lang.Object
-
- g2401_2500.s2465_number_of_distinct_averages.Solution
-
public class Solution extends Object
2465 - Number of Distinct Averages.Easy
You are given a 0-indexed integer array
nums
of even length.As long as
nums
is not empty, you must repetitively:- Find the minimum number in
nums
and remove it. - Find the maximum number in
nums
and remove it. - Calculate the average of the two removed numbers.
The average of two numbers
a
andb
is(a + b) / 2
.- For example, the average of
2
and3
is(2 + 3) / 2 = 2.5
.
Return the number of distinct averages calculated using the above process.
Note that when there is a tie for a minimum or maximum number, any can be removed.
Example 1:
Input: nums = [4,1,4,0,3,5]
Output: 2
Explanation:
-
Remove 0 and 5, and the average is (0 + 5) / 2 = 2.5. Now, nums = [4,1,4,3].
-
Remove 1 and 4. The average is (1 + 4) / 2 = 2.5, and nums = [4,3].
-
Remove 3 and 4, and the average is (3 + 4) / 2 = 3.5.
Since there are 2 distinct numbers among 2.5, 2.5, and 3.5, we return 2.
Example 2:
Input: nums = [1,100]
Output: 1
Explanation:
There is only one average to be calculated after removing 1 and 100, so we return 1.
Constraints:
2 <= nums.length <= 100
nums.length
is even.0 <= nums[i] <= 100
- Find the minimum number in
-
-
Constructor Summary
Constructors Constructor Description Solution()
-
Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description int
distinctAverages(int[] nums)
-