Package g1201_1300.s1283_find_the_smallest_divisor_given_a_threshold

Class Solution

java.lang.Object
g1201_1300.s1283_find_the_smallest_divisor_given_a_threshold.Solution
public class Solution extends java.lang.Object
1283 - Find the Smallest Divisor Given a Threshold.

Medium

Given an array of integers nums and an integer threshold, we will choose a positive integer divisor, divide all the array by it, and sum the division’s result. Find the smallest divisor such that the result mentioned above is less than or equal to threshold.

Each result of the division is rounded to the nearest integer greater than or equal to that element. (For example: 7/3 = 3 and 10/2 = 5).

The test cases are generated so that there will be an answer.

Example 1:

Input: nums = [1,2,5,9], threshold = 6

Output: 5

Explanation: We can get a sum to 17 (1+2+5+9) if the divisor is 1. If the divisor is 4 we can get a sum of 7 (1+1+2+3) and if the divisor is 5 the sum will be 5 (1+1+1+2).

Example 2:

Input: nums = [44,22,33,11,1], threshold = 5

Output: 44

Constraints:

  • 1 <= nums.length <= 5 * 104
  • 1 <= nums[i] <= 106
  • nums.length <= threshold <= 106

  • Constructor Summary

    Constructors
    Constructor
    Description
    Solution()
     

  • Method Summary

    Modifier and Type
    Method
    Description
    int
    smallestDivisor(int[] nums, int threshold)
     

    Methods inherited from class java.lang.Object

    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • smallestDivisor

      public int smallestDivisor(int[] nums, int threshold)