Class Solution
Easy
Given an array of integers nums
, you start with an initial positive value startValue_._
In each iteration, you calculate the step by step sum of startValue plus elements in nums
(from left to right).
Return the minimum positive value of startValue such that the step by step sum is never less than 1.
Example 1:
Input: nums = [-3,2,-3,4,2]
Output: 5
Explanation: If you choose startValue = 4, in the third iteration your step by step sum is less than 1.
step by step sum
startValue = 4 | startValue = 5 | nums
(4 -3 ) = 1 | (5 -3 ) = 2 | -3
(1 +2 ) = 3 | (2 +2 ) = 4 | 2
(3 -3 ) = 0 | (4 -3 ) = 1 | -3
(0 +4 ) = 4 | (1 +4 ) = 5 | 4
(4 +2 ) = 6 | (5 +2 ) = 7 | 2
Example 2:
Input: nums = [1,2]
Output: 1
Explanation: Minimum start value should be positive.
Example 3:
Input: nums = [1,-2,-3]
Output: 5
Constraints:
1 <= nums.length <= 100
-100 <= nums[i] <= 100
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Constructor Summary
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Method Summary
Methods inherited from class java.lang.Object
clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
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Constructor Details
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Solution
public Solution()
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Method Details
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minStartValue
public int minStartValue(int[] nums)
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