Class Solution
Easy
Given a sentence
that consists of some words separated by a single space , and a searchWord
, check if searchWord
is a prefix of any word in sentence
.
Return the index of the word in sentence
( 1-indexed ) where searchWord
is a prefix of this word. If searchWord
is a prefix of more than one word, return the index of the first word (minimum index). If there is no such word return -1
.
A prefix of a string s
is any leading contiguous substring of s
.
Example 1:
Input: sentence = “i love eating burger”, searchWord = “burg”
Output: 4
Explanation: “burg” is prefix of “burger” which is the 4th word in the sentence.
Example 2:
Input: sentence = “this problem is an easy problem”, searchWord = “pro”
Output: 2
Explanation: “pro” is prefix of “problem” which is the 2nd and the 6th word in the sentence, but we return 2 as it’s the minimal index.
Example 3:
Input: sentence = “i am tired”, searchWord = “you”
Output: -1
Explanation: “you” is not a prefix of any word in the sentence.
Constraints:
1 <= sentence.length <= 100
1 <= searchWord.length <= 10
sentence
consists of lowercase English letters and spaces.searchWord
consists of lowercase English letters.
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Constructor Summary
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Method Summary
Modifier and TypeMethodDescriptionint
isPrefixOfWord
(java.lang.String sentence, java.lang.String searchWord) Methods inherited from class java.lang.Object
clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
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Constructor Details
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Solution
public Solution()
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Method Details
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isPrefixOfWord
public int isPrefixOfWord(java.lang.String sentence, java.lang.String searchWord)
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