Class Solution
Easy
You are given two strings current
and correct
representing two 24-hour times.
24-hour times are formatted as "HH:MM"
, where HH
is between 00
and 23
, and MM
is between 00
and 59
. The earliest 24-hour time is 00:00
, and the latest is 23:59
.
In one operation you can increase the time current
by 1
, 5
, 15
, or 60
minutes. You can perform this operation any number of times.
Return the minimum number of operations needed to convert current
to correct
.
Example 1:
Input: current = “02:30”, correct = “04:35”
Output: 3
Explanation:
We can convert current to correct in 3 operations as follows:
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Add 60 minutes to current. current becomes “03:30”.
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Add 60 minutes to current. current becomes “04:30”.
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Add 5 minutes to current. current becomes “04:35”.
It can be proven that it is not possible to convert current to correct in fewer than 3 operations.
Example 2:
Input: current = “11:00”, correct = “11:01”
Output: 1
Explanation: We only have to add one minute to current, so the minimum number of operations needed is 1.
Constraints:
current
andcorrect
are in the format"HH:MM"
current <= correct
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Constructor Summary
Constructors -
Method Summary
Modifier and TypeMethodDescriptionint
convertTime
(java.lang.String current, java.lang.String correct) Methods inherited from class java.lang.Object
clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
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Constructor Details
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Solution
public Solution()
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Method Details
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convertTime
public int convertTime(java.lang.String current, java.lang.String correct)
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