Class Solution
Easy
You are given a 0-indexed integer array nums
of even length.
As long as nums
is not empty, you must repetitively:
- Find the minimum number in
nums
and remove it. - Find the maximum number in
nums
and remove it. - Calculate the average of the two removed numbers.
The average of two numbers a
and b
is (a + b) / 2
.
- For example, the average of
2
and3
is(2 + 3) / 2 = 2.5
.
Return the number of distinct averages calculated using the above process.
Note that when there is a tie for a minimum or maximum number, any can be removed.
Example 1:
Input: nums = [4,1,4,0,3,5]
Output: 2
Explanation:
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Remove 0 and 5, and the average is (0 + 5) / 2 = 2.5. Now, nums = [4,1,4,3].
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Remove 1 and 4. The average is (1 + 4) / 2 = 2.5, and nums = [4,3].
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Remove 3 and 4, and the average is (3 + 4) / 2 = 3.5.
Since there are 2 distinct numbers among 2.5, 2.5, and 3.5, we return 2.
Example 2:
Input: nums = [1,100]
Output: 1
Explanation:
There is only one average to be calculated after removing 1 and 100, so we return 1.
Constraints:
2 <= nums.length <= 100
nums.length
is even.0 <= nums[i] <= 100
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Constructor Summary
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Method Summary
Methods inherited from class java.lang.Object
clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait
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Constructor Details
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Solution
public Solution()
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Method Details
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distinctAverages
public int distinctAverages(int[] nums)
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