Class Solution
java.lang.Object
g1501_1600.s1582_special_positions_in_a_binary_matrix.Solution
1582 - Special Positions in a Binary Matrix.
Easy
Given an m x n binary matrix mat, return the number of special positions in mat.
A position (i, j) is called special if mat[i][j] == 1 and all other elements in row i and column j are 0 (rows and columns are 0-indexed ).
Example 1:

Input: mat = [[1,0,0],[0,0,1],[1,0,0]]
Output: 1
Explanation: (1, 2) is a special position because mat[1][2] == 1 and all other elements in row 1 and column 2 are 0.
Example 2:

Input: mat = [[1,0,0],[0,1,0],[0,0,1]]
Output: 3
Explanation: (0, 0), (1, 1) and (2, 2) are special positions.
Constraints:
m == mat.lengthn == mat[i].length1 <= m, n <= 100mat[i][j]is either0or1.
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Solution
public Solution()
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numSpecial
public int numSpecial(int[][] mat)
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