Class Solution
Medium
Two strings are considered close if you can attain one from the other using the following operations:
- Operation 1: Swap any two existing characters.
- For example,
abcde -> aecdb
- For example,
- Operation 2: Transform every occurrence of one existing character into another existing character, and do the same with the other character.
- For example,
aacabb -> bbcbaa(alla’s turn intob’s, and allb’s turn intoa’s)
- For example,
You can use the operations on either string as many times as necessary.
Given two strings, word1 and word2, return true if word1 and word2 are close , and false otherwise.
Example 1:
Input: word1 = “abc”, word2 = “bca”
Output: true
Explanation: You can attain word2 from word1 in 2 operations.
Apply Operation 1: “abc” -> “acb”
Apply Operation 1: “acb” -> “bca”
Example 2:
Input: word1 = “a”, word2 = “aa”
Output: false
Explanation: It is impossible to attain word2 from word1, or vice versa, in any number of operations.
Example 3:
Input: word1 = “cabbba”, word2 = “abbccc”
Output: true
Explanation: You can attain word2 from word1 in 3 operations.
Apply Operation 1: “cabbba” -> “caabbb”
Apply Operation 2: "caabbb" -> “baaccc”
Apply Operation 2: “baaccc” -> “abbccc”
Constraints:
1 <= word1.length, word2.length <= 105word1andword2contain only lowercase English letters.
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Constructor Summary
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Constructor Details
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Solution
public Solution()
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Method Details
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closeStrings
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