Package g1901_2000.s2000_reverse_prefix_of_word

Class Solution

java.lang.Object
g1901_2000.s2000_reverse_prefix_of_word.Solution
public class Solution extends Object
2000 - Reverse Prefix of Word.

Easy

Given a 0-indexed string word and a character ch, reverse the segment of word that starts at index 0 and ends at the index of the first occurrence of ch ( inclusive ). If the character ch does not exist in word, do nothing.

  • For example, if word = "abcdefd" and ch = "d", then you should reverse the segment that starts at 0 and ends at 3 ( inclusive ). The resulting string will be "dcbaefd".

Return the resulting string.

Example 1:

Input: word = “abcdefd”, ch = “d”

Output: “dcbaefd”

Explanation: The first occurrence of “d” is at index 3.

Reverse the part of word from 0 to 3 (inclusive), the resulting string is “dcbaefd”.

Example 2:

Input: word = “xyxzxe”, ch = “z”

Output: “zxyxxe”

Explanation: The first and only occurrence of “z” is at index 3.

Reverse the part of word from 0 to 3 (inclusive), the resulting string is “zxyxxe”.

Example 3:

Input: word = “abcd”, ch = “z”

Output: “abcd”

Explanation: “z” does not exist in word.

You should not do any reverse operation, the resulting string is “abcd”.

Constraints:

  • 1 <= word.length <= 250
  • word consists of lowercase English letters.
  • ch is a lowercase English letter.

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • reversePrefix

      public String reversePrefix(String word, char ch)