Package g2301_2400.s2382_maximum_segment_sum_after_removals

Class Solution

java.lang.Object
g2301_2400.s2382_maximum_segment_sum_after_removals.Solution
public class Solution extends Object
2382 - Maximum Segment Sum After Removals.

Hard

You are given two 0-indexed integer arrays nums and removeQueries, both of length n. For the ith query, the element in nums at the index removeQueries[i] is removed, splitting nums into different segments.

A segment is a contiguous sequence of positive integers in nums. A segment sum is the sum of every element in a segment.

Return an integer array answer, of length n, where answer[i] is the maximum segment sum after applying the ith removal.

Note: The same index will not be removed more than once.

Example 1:

Input: nums = [1,2,5,6,1], removeQueries = [0,3,2,4,1]

Output: [14,7,2,2,0]

Explanation: Using 0 to indicate a removed element, the answer is as follows:

Query 1: Remove the 0th element, nums becomes [0,2,5,6,1] and the maximum segment sum is 14 for segment [2,5,6,1].

Query 2: Remove the 3rd element, nums becomes [0,2,5,0,1] and the maximum segment sum is 7 for segment [2,5].

Query 3: Remove the 2nd element, nums becomes [0,2,0,0,1] and the maximum segment sum is 2 for segment [2].

Query 4: Remove the 4th element, nums becomes [0,2,0,0,0] and the maximum segment sum is 2 for segment [2].

Query 5: Remove the 1st element, nums becomes [0,0,0,0,0] and the maximum segment sum is 0, since there are no segments.

Finally, we return [14,7,2,2,0].

Example 2:

Input: nums = [3,2,11,1], removeQueries = [3,2,1,0]

Output: [16,5,3,0]

Explanation: Using 0 to indicate a removed element, the answer is as follows:

Query 1: Remove the 3rd element, nums becomes [3,2,11,0] and the maximum segment sum is 16 for segment [3,2,11].

Query 2: Remove the 2nd element, nums becomes [3,2,0,0] and the maximum segment sum is 5 for segment [3,2].

Query 3: Remove the 1st element, nums becomes [3,0,0,0] and the maximum segment sum is 3 for segment [3].

Query 4: Remove the 0th element, nums becomes [0,0,0,0] and the maximum segment sum is 0, since there are no segments.

Finally, we return [16,5,3,0].

Constraints:

  • n == nums.length == removeQueries.length
  • 1 <= n <= 105
  • 1 <= nums[i] <= 109
  • 0 <= removeQueries[i] < n
  • All the values of removeQueries are unique.

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • maximumSegmentSum

      public long[] maximumSegmentSum(int[] nums, int[] removeQueries)