Package g2701_2800.s2740_find_the_value_of_the_partition

Class Solution

java.lang.Object
g2701_2800.s2740_find_the_value_of_the_partition.Solution
public class Solution extends Object
2740 - Find the Value of the Partition.

Medium

You are given a positive integer array nums.

Partition nums into two arrays, nums1 and nums2, such that:

  • Each element of the array nums belongs to either the array nums1 or the array nums2.
  • Both arrays are non-empty.
  • The value of the partition is minimized.

The value of the partition is |max(nums1) - min(nums2)|.

Here, max(nums1) denotes the maximum element of the array nums1, and min(nums2) denotes the minimum element of the array nums2.

Return the integer denoting the value of such partition.

Example 1:

Input: nums = [1,3,2,4]

Output: 1

Explanation: We can partition the array nums into nums1 = [1,2] and nums2 = [3,4].

  • The maximum element of the array nums1 is equal to 2.
  • The minimum element of the array nums2 is equal to 3.

The value of the partition is |2 - 3| = 1.

It can be proven that 1 is the minimum value out of all partitions.

Example 2:

Input: nums = [100,1,10]

Output: 9

Explanation: We can partition the array nums into nums1 = [10] and nums2 = [100,1].

  • The maximum element of the array nums1 is equal to 10.
  • The minimum element of the array nums2 is equal to 1.

The value of the partition is |10 - 1| = 9.

It can be proven that 9 is the minimum value out of all partitions.

Constraints:

  • 2 <= nums.length <= 105
  • 1 <= nums[i] <= 109

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • findValueOfPartition

      public int findValueOfPartition(int[] nums)