Class Solution
java.lang.Object
g3201_3300.s3271_hash_divided_string.Solution
3271 - Hash Divided String.
Medium
You are given a string s of length n and an integer k, where n is a multiple of k. Your task is to hash the string s into a new string called result, which has a length of n / k.
First, divide s into n / k substrings , each with a length of k. Then, initialize result as an empty string.
For each substring in order from the beginning:
- The hash value of a character is the index of that character in the English alphabet (e.g.,
'a' → 0,'b' → 1, …,'z' → 25). - Calculate the sum of all the hash values of the characters in the substring.
- Find the remainder of this sum when divided by 26, which is called
hashedChar. - Identify the character in the English lowercase alphabet that corresponds to
hashedChar. - Append that character to the end of
result.
Return result.
Example 1:
Input: s = “abcd”, k = 2
Output: “bf”
Explanation:
First substring: "ab", 0 + 1 = 1, 1 % 26 = 1, result[0] = 'b'.
Second substring: "cd", 2 + 3 = 5, 5 % 26 = 5, result[1] = 'f'.
Example 2:
Input: s = “mxz”, k = 3
Output: “i”
Explanation:
The only substring: "mxz", 12 + 23 + 25 = 60, 60 % 26 = 8, result[0] = 'i'.
Constraints:
1 <= k <= 100k <= s.length <= 1000s.lengthis divisible byk.sconsists only of lowercase English letters.
-
Constructor Summary
Constructors -
Method Summary
-
Constructor Details
-
Solution
public Solution()
-
-
Method Details
-
stringHash
-