Class Solution
java.lang.Object
g3701_3800.s3701_compute_alternating_sum.Solution
3701 - Compute Alternating Sum.
Easy
You are given an integer array nums.
The alternating sum of nums is the value obtained by adding elements at even indices and subtracting elements at odd indices. That is, nums[0] - nums[1] + nums[2] - nums[3]...
Return an integer denoting the alternating sum of nums.
Example 1:
Input: nums = [1,3,5,7]
Output: -4
Explanation:
- Elements at even indices are
nums[0] = 1andnums[2] = 5because 0 and 2 are even numbers. - Elements at odd indices are
nums[1] = 3andnums[3] = 7because 1 and 3 are odd numbers. - The alternating sum is
nums[0] - nums[1] + nums[2] - nums[3] = 1 - 3 + 5 - 7 = -4.
Example 2:
Input: nums = [100]
Output: 100
Explanation:
- The only element at even indices is
nums[0] = 100because 0 is an even number. - There are no elements on odd indices.
- The alternating sum is
nums[0] = 100.
Constraints:
1 <= nums.length <= 1001 <= nums[i] <= 100
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Constructor Details
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Solution
public Solution()
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Method Details
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alternatingSum
public int alternatingSum(int[] nums)
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