Class Solution
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public final class Solution975 - Odd Even Jump\.
Hard
You are given an integer array
arr. From some starting index, you can make a series of jumps. The (1<sup>st</sup>, 3<sup>rd</sup>, 5<sup>th</sup>, ...) jumps in the series are called odd-numbered jumps , and the (2<sup>nd</sup>, 4<sup>th</sup>, 6<sup>th</sup>, ...) jumps in the series are called even-numbered jumps. Note that the jumps are numbered, not the indices.You may jump forward from index
ito indexj(withi < j) in the following way:During odd-numbered jumps (i.e., jumps 1, 3, 5, ...), you jump to the index
jsuch thatarr[i] <= arr[j]andarr[j]is the smallest possible value. If there are multiple such indicesj, you can only jump to the smallest such indexj.During even-numbered jumps (i.e., jumps 2, 4, 6, ...), you jump to the index
jsuch thatarr[i] >= arr[j]andarr[j]is the largest possible value. If there are multiple such indicesj, you can only jump to the smallest such indexj.It may be the case that for some index
i, there are no legal jumps.
A starting index is good if, starting from that index, you can reach the end of the array (index
arr.length - 1) by jumping some number of times (possibly 0 or more than once).Return the number of good starting indices.
Example 1:
Input: arr = 10,13,12,14,15
Output: 2
Explanation:
From starting index i = 0, we can make our 1st jump to i = 2 (since arr2 is the smallest among arr1,
arr2, arr3, arr4 that is greater or equal to arr0), then we cannot jump any more.
From starting index i = 1 and i = 2, we can make our 1st jump to i = 3, then we cannot jump any more.
From starting index i = 3, we can make our 1st jump to i = 4, so we have reached the end.
From starting index i = 4, we have reached the end already.
In total, there are 2 different starting indices i = 3 and i = 4, where we can reach the end with some number of jumps.
Example 2:
Input: arr = 2,3,1,1,4
Output: 3
Explanation:
From starting index i = 0, we make jumps to i = 1, i = 2, i = 3:
During our 1st jump (odd-numbered), we first jump to i = 1 because arr1 is the smallest value in [arr1,
arr2, arr3, arr4] that is greater than or equal to arr0.
During our 2nd jump (even-numbered), we jump from i = 1 to i = 2 because arr2 is the largest value in
[arr2, arr3, arr4] that is less than or equal to arr1. arr3 is also the largest value, but 2 is a
smaller index, so we can only jump to i = 2 and not i = 3
During our 3rd jump (odd-numbered), we jump from i = 2 to i = 3 because arr3 is the smallest value in
[arr3, arr4] that is greater than or equal to arr2.
We can't jump from i = 3 to i = 4, so the starting index i = 0 is not good.
In a similar manner, we can deduce that: From starting index i = 1, we jump to i = 4, so we reach the end.
From starting index i = 2, we jump to i = 3, and then we can't jump anymore.
From starting index i = 3, we jump to i = 4, so we reach the end.
From starting index i = 4, we are already at the end.
In total, there are 3 different starting indices i = 1, i = 3, and i = 4, where we can reach the end with
some number of jumps.
Example 3:
Input: arr = 5,1,3,4,2
Output: 3
Explanation: We can reach the end from starting indices 1, 2, and 4.
Constraints:
<code>1 <= arr.length <= 2 * 10<sup>4</sup></code>
<code>0 <= arri< 10<sup>5</sup></code>
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final IntegeroddEvenJumps(IntArray arr)-
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Method Detail
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oddEvenJumps
final Integer oddEvenJumps(IntArray arr)
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