Class Solution
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- All Implemented Interfaces:
public final class Solution994 - Rotting Oranges\.
Medium
You are given an
m x ngridwhere each cell can have one of three values:0representing an empty cell,1representing a fresh orange, or2representing a rotten orange.
Every minute, any fresh orange that is 4-directionally adjacent to a rotten orange becomes rotten.
Return the minimum number of minutes that must elapse until no cell has a fresh orange. If this is impossible, return
-1.Example 1:
Input: grid = \[\[2,1,1],1,1,0,0,1,1]
Output: 4
Example 2:
Input: grid = \[\[2,1,1],0,1,1,1,0,1]
Output: -1
Explanation: The orange in the bottom left corner (row 2, column 0) is never rotten, because rotting only happens 4-directionally.
Example 3:
Input: grid = \[\[0,2]]
Output: 0
Explanation: Since there are already no fresh oranges at minute 0, the answer is just 0.
Constraints:
m == grid.lengthn == grid[i].length1 <= m, n <= 10grid[i][j]is0,1, or2.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final IntegerorangesRotting(Array<IntArray> grid)-
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Method Detail
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orangesRotting
final Integer orangesRotting(Array<IntArray> grid)
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